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Question Number 34357 by math1967 last updated on 05/May/18
If a+b+c=0  prove that  i)((a/(b+c))+ (b/(c+a)) +(c/(a+b)))(((b+c)/a) +((c+a)/b) +((a+b)/c))=9  ii)((a/(b−c)) +(b/(c−a)) +(c/(a−b)))(((b−c)/a) +((c−a)/b) +((a−b)/c))=9
Ifa+b+c=0provethati)(ab+c+bc+a+ca+b)(b+ca+c+ab+a+bc)=9ii)(abc+bca+cab)(bca+cab+abc)=9
Answered by tanmay.chaudhury50@gmail.com last updated on 05/May/18
i){((a/(b+c))+1−1)+((b/(c+a))+1−1)+((c/(a+b))+1−1)}×  {(((b+c)/a)+1−1)+(((c+a)/b)+1−1)+(((a+b)/c)+1−1)}  ={(((a+b+c)/(b+c))−1)+(((a+b+c)/(c+a))−1)+(((a+b+c)/(a+b))−1)}×  {(((a+b+c)/a)−1)+(((a+b+c)/b)−1)+(((a+b+c)/c)−1)}  =given a+b+c=0 so  =(−3)×(−3)=9
i){(ab+c+11)+(bc+a+11)+(ca+b+11)}×{(b+ca+11)+(c+ab+11)+(a+bc+11)}={(a+b+cb+c1)+(a+b+cc+a1)+(a+b+ca+b1)}×{(a+b+ca1)+(a+b+cb1)+(a+b+cc1)}=givena+b+c=0so=(3)×(3)=9

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