Question Number 37037 by jayanta11 last updated on 08/Jun/18

Answered by math1967 last updated on 08/Jun/18
![3)a=b=c ((a+b)/(a+b))−(c/(a+b))=((b+c)/(b+c))−(a/(b+c))=((c+a)/(c+a))−(b/(c+a)) (c/(a+b))=(a/(b+c))=(b/(c+a)) ((a+b)/c)+1=((b+c)/a)+1=((c+a)/b)+1 ((a+b+c)/c)=((a+b+c)/a)=((a+b+c)/b) (1/c)=(1/a)=(1/b) [(a+b+c)≠0] ∴c=a=b⇒a=b=c](https://www.tinkutara.com/question/Q37039.png)
Commented by Rasheed.Sindhi last updated on 08/Jun/18

Answered by Rasheed.Sindhi last updated on 08/Jun/18

Answered by ajfour last updated on 08/Jun/18

Answered by tanmay.chaudhury50@gmail.com last updated on 08/Jun/18
