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if-a-b-c-gt-0-and-a-b-c-1-find-min-1-a-9-b-25-c-a-73-b-75-c-105-d-81-e-83-




Question Number 150880 by mathdanisur last updated on 16/Aug/21
if  a;b;c>0  and  a+b+c=1  find min((1/a) + (9/b) + ((25)/c)) = ?  a)73   b)75   c)105   d)81   e)83
ifa;b;c>0anda+b+c=1findmin(1a+9b+25c)=?a)73b)75c)105d)81e)83
Answered by mr W last updated on 16/Aug/21
s=(1/a)+(9/b)+((25)/(1−a−b))  (∂s/∂a)=−(1/a^2 )+((25)/((1−a−b)^2 ))=0  (1/a)=(5/(1−a−b))  (∂s/∂b)=−(9/b^2 )+((25)/((1−a−b)^2 ))=0  (3/b)=(5/(1−a−b))=(1/a)  ⇒b=3a  ⇒a=(1/9)  ⇒b=(1/3)  ⇒c=(5/9)  s_(min) =9+9×3+25×(9/5)=81
s=1a+9b+251absa=1a2+25(1ab)2=01a=51absb=9b2+25(1ab)2=03b=51ab=1ab=3aa=19b=13c=59smin=9+9×3+25×95=81
Commented by mathdanisur last updated on 16/Aug/21
Thank you Ser
ThankyouSer
Answered by qaz last updated on 16/Aug/21
By Cauthy Schwarz inequality in engel form:  (1/a)+(9/b)+((25)/c)≥(((1+3+5)^2 )/(a+b+c))=81
ByCauthySchwarzinequalityinengelform:1a+9b+25c(1+3+5)2a+b+c=81
Commented by mathdanisur last updated on 16/Aug/21
Thank you Ser
ThankyouSer

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