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if-a-b-c-R-find-abc-1-3-1-a-1-2b-1-4c-min-




Question Number 145383 by mathdanisur last updated on 04/Jul/21
if  a;b;c∈R^+   find  (((abc))^(1/3)  + (1/a) + (1/(2b)) + (1/(4c)))_(min) = ?
ifa;b;cR+find(abc3+1a+12b+14c)min=?
Answered by mnjuly1970 last updated on 04/Jul/21
 A ≥ ((abc))^(1/3)  +3((1/(8abc)))^(1/3)         =((abc))^(1/3)  +(3/2)((1/(abc)))^(1/3)  ≥^(am−gm) 2 (√(3/2))   A_( min)  = 2 (√(3/2)) =(√6)
Aabc3+318abc3=abc3+321abc3amgm232Amin=232=6
Commented by mathdanisur last updated on 04/Jul/21
Thanks Sir, answer (√6)
ThanksSir,answer6
Commented by mnjuly1970 last updated on 04/Jul/21
 thank you so much and   your mention ...
thankyousomuchandyourmention
Commented by mathdanisur last updated on 04/Jul/21
cool Ser, thank you
coolSer,thankyou
Answered by ajfour last updated on 04/Jul/21
let  (1/a)=x  ,  (1/(2b))=y , (1/(4c))=z  ⇒ f(x,y,z)=((1/2)/((xyz)^(1/3) ))+x+y+z  minimum should of course  be when x=y=z  (symmetry)  ⇒ f_(min) =(1/(2x))+3x      where   (1/(2x))=3x  ⇒  x^2 =(1/6)     f_(min) = 6x = ((  6)/( (√6))) = (√6) .
let1a=x,12b=y,14c=zf(x,y,z)=1/2(xyz)1/3+x+y+zminimumshouldofcoursebewhenx=y=z(symmetry)fmin=12x+3xwhere12x=3xx2=16fmin=6x=66=6.
Commented by mathdanisur last updated on 04/Jul/21
cool Ser, thank you
coolSer,thankyou

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