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if-a-b-R-and-a-2-1-b-2-1-9-6-a-b-find-a-2-b-2-




Question Number 151391 by mathdanisur last updated on 20/Aug/21
if  a;b∈R  and  (a^2 +1)(b^2 +1)+9=6(a+b)  find  a^2 +b^2 =?
ifa;bRand(a2+1)(b2+1)+9=6(a+b)finda2+b2=?
Answered by dumitrel last updated on 20/Aug/21
(a^2 +1)(b^2 +1)≥^(cbs) (a+b)^2 ⇒  6(a+b)≥(a+b)^2 +9⇒(a+b−3)^2 ≤0  a+b=3⇒(ab)^2 +9−2ab+1=9⇒ab=1⇒  a^2 +b^2 =7
(a2+1)(b2+1)cbs(a+b)26(a+b)(a+b)2+9(a+b3)20a+b=3(ab)2+92ab+1=9ab=1a2+b2=7
Commented by mathdanisur last updated on 20/Aug/21
Thank You Ser Cool
ThankYouSerCool

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