If-a-number-is-20-more-the-other-how-much-percent-is-the-second-number-less-than-the-first-please-help-

Question Number 177179 by Mastermind last updated on 01/Oct/22

If a number is 20 % more the other, how

much percent is the second number

less than the first .

please help!

Commented by Frix last updated on 02/Oct/22

{it}^{'} s simply multiplying and dividing

x + 20 % = y \overset{1 + \frac{20}{100} = 1.2}{\Leftrightarrow} 1.2 x = y

\Rightarrow

x = \frac{y}{1.2} \Leftrightarrow x = . 8 \bar{3} y \overset{1 - \frac{16 . \bar{6}}{100} = . 8 \bar{3}}{\Leftrightarrow} y - 16 . \bar{6 %} = x

Answered by JDamian last updated on 01/Oct/22

b = a + a \frac{20}{100} = 1.2 a

\frac{b - a}{b} \times 100 = \frac{1.2 a - a}{1.2 a} \times 100 =

= \frac{1.2 - 1}{1.2} \times 100 = \frac{0.2}{1.2} \times 100 = \frac{20}{1.2} = 16 . \hat{6 %}

Commented by Mastermind last updated on 02/Oct/22

correct that what i got here, thanks man

Commented by peter frank last updated on 02/Oct/22

thanks