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Question Number 56904 by pete last updated on 26/Mar/19
If α and β are the roots of of the equation  3x^2 −x−3=0, find thevalue of (α^2 −β^2 )  if α>β.
Ifαandβaretherootsofoftheequation3x2x3=0,findthevalueof(α2β2)ifα>β.
Answered by tanmay.chaudhury50@gmail.com last updated on 26/Mar/19
(α−β)^2 =(α+β)^2 −4αβ  α+β=((−b)/a)=((−(−1))/3)=(1/3)  αβ=(c/a)=((−3)/3)=−1                    (α−β)^2 =(α+β)^2 −4αβ                                     =(1/9)+4=((37)/9)  (α−β)=((√(37))/3)  α^2 −β^2 =(α+β)(α−β)                =(1/3)×((√(37))/3)=((√(37))/9)
(αβ)2=(α+β)24αβα+β=ba=(1)3=13αβ=ca=33=1(αβ)2=(α+β)24αβ=19+4=379(αβ)=373α2β2=(α+β)(αβ)=13×373=379
Commented by pete last updated on 26/Mar/19
Thanks for your help.
Thanksforyourhelp.
Commented by tanmay.chaudhury50@gmail.com last updated on 26/Mar/19
most welcome...
mostwelcome

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