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If-c-is-the-line-segement-from-0-0-0-to-1-2-3-find-x-e-yz-ds-




Question Number 50689 by Tawa1 last updated on 18/Dec/18
If  c is the line segement from  (0, 0, 0) to (1, 2, 3)  find   ∫ x e^(yz)   ds
Ifcisthelinesegementfrom(0,0,0)to(1,2,3)findxeyzds
Answered by mr W last updated on 19/Dec/18
((x−1)/1)=((y−2)/2)=((z−3)/3)  ⇒y=2x  ⇒z=3x  ds=(√((dx)^2 +(dy)^2 +(dz)^2 ))=(√(1+2^2 +3^2 ))dx=(√(14))dx  ∫xe^(yz) ds=∫_0 ^1 xe^(6x^2 ) (√(14)) dx  =((√(14))/(12))∫_0 ^1 e^(6x^2 )  d(6x^2 )  =((√(14))/(12))[e^(6x^2 ) ]_0 ^1   =((√(14))/(12))(e^6 −1)
x11=y22=z33y=2xz=3xds=(dx)2+(dy)2+(dz)2=1+22+32dx=14dxxeyzds=01xe6x214dx=141201e6x2d(6x2)=1412[e6x2]01=1412(e61)
Commented by Tawa1 last updated on 19/Dec/18
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