if-f-0-and-d-dx-f-x-2-f-x-2-and-f-0-1-find-f-x-if-f-x-4x-3-x-2-1-find-f-1-x-and-f-1-2- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 85653 by M±th+et£s last updated on 23/Mar/20 iff⩾0andddx(f(x))2=(f′(x))2andf(0)=1findf(x)iff(x)=4x3x2+1findf−1(x)and(f−1)′(2) Commented by john santu last updated on 24/Mar/20 (1)2f(x)f′(x)=(f′(x))2f′(x)[f′(x)−2f(x)]=0⇒f′(x)=0⇒f(x)=k,k=constanf(0)=1⇒k=1⇒f(x)=1⇒f′(x)=2f(x)df(x)=2f(x)dx∫df(x)=∫2f(x)dxf(x)=2∫f(x)dx Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: The-value-of-a-for-which-the-equation-1-a-2-x-2-2ax-1-0-has-roots-belonging-to-0-1-is-Next Next post: The-quadratic-equations-x-2-6x-a-0-and-x-2-cx-6-0-have-one-root-in-common-The-other-roots-of-the-first-and-second-equations-are-integers-in-the-ratio-4-3-Then-find-the-common-root- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![(1) 2f(x) f ′(x) = (f ′(x))^2 f ′(x)[ f ′(x)−2f(x)] = 0 ⇒f ′(x) = 0 ⇒ f(x) = k , k=constan f(0) = 1 ⇒ k = 1 ⇒f(x)=1 ⇒f ′(x) = 2f(x) df(x) = 2f(x) dx ∫ df(x) = ∫ 2f(x) dx f(x)= 2∫f(x)dx](https://www.tinkutara.com/question/Q85679.png)