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if-f-f-f-f-x-16x-15-find-f-x-




Question Number 151080 by malwan last updated on 18/Aug/21
if (f○f○f○f)(x)=16x+15  find f(x)
if(ffff)(x)=16x+15findf(x)
Answered by Mokmokhi last updated on 18/Aug/21
It is reasonable to say f(x) is linear by rejecting other possibilities.  Then f(x)=ax+b for some unknowns a and b.  The value of a should be 2 or −2.  If a=2. b=1.  If a=−2. b=20.
Itisreasonabletosayf(x)islinearbyrejectingotherpossibilities.Thenf(x)=ax+bforsomeunknownsaandb.Thevalueofashouldbe2or2.Ifa=2.b=1.Ifa=2.b=20.
Commented by malwan last updated on 18/Aug/21
thank you sir
thankyousir
Answered by qaz last updated on 18/Aug/21
let f(x)=x ,we get fixed point x=−1  so f(x)=16(x+1)−1  ⇒(f○f)(x)=16^2 (x+1)−1       (f○f○f)(x)=16^3 (x+1)−1        (f○f○f○f)(x)=16^4 (x+1)−1        (f○f○...○f_(n) )(x)=16^n (x+1)−1
letf(x)=x,wegetfixedpointx=1sof(x)=16(x+1)1(ff)(x)=162(x+1)1(fff)(x)=163(x+1)1(ffff)(x)=164(x+1)1(fffn)(x)=16n(x+1)1
Commented by malwan last updated on 18/Aug/21
thank you sir
thankyousir
Commented by qaz last updated on 19/Aug/21
sorry.there is a error.  we need make a reverse iteration.  (f○f○f○f)(x)=2^4 (x+1)−1  ....  f(x)=2(x+1)−1=2x+1
sorry.thereisaerror.weneedmakeareverseiteration.(ffff)(x)=24(x+1)1.f(x)=2(x+1)1=2x+1

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