If-f-R-R-is-a-polynomial-function-which-satisfy-the-equation-f-f-x-f-x-12x-x-R-then-find-f-x- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 22133 by Tinkutara last updated on 11/Oct/17 Iff:R+→R+isapolynomialfunctionwhichsatisfytheequationf(f(x))+f(x)=12x∀x∈R+,thenfindf(x). Commented by Rasheed.Sindhi last updated on 22/Oct/17 f(f(x))+f(x)=12xCase−1:f(x)islinearLetf(x)=ax+bf(f(x))+f(x)=12x⇒{a(ax+b)+b}+ax+b=12xa2x+ab+b+ax+b=12x(a2+a)x+ab+2b=12xComparingcoefficients:a2+a=12∧ab+2b=0(a−3)(a+4)=0∧b(a+2)=0(a=3∣a=−4)∧(b=0∣a=−2)f(x)=3x,f(x)=−4xIff(x)islinearthenf(x)=3xorf(x)=−4x Answered by ajfour last updated on 14/Oct/17 letf(x)=yAsf(y)+f(x)=12x⇒dfdy×f′(x)+f′(x)=12or(dfdy+1)f′(x)=12⇒dfdy=constant&f′(x)=constantletf′(x)=a,thendfdy=12a−1..(i)⇒f′(x)=ax+b(..say)f(y)=ay+banddfdy=a…(ii)from(i)and(ii):a=12a−1⇒a2+a−12=0⇒a=−4,3nowf(y)+f(x)=12x⇒(ay+b)+(ax+b)=12x⇒[a(ax+b)+b]+ax+b=12xor(a2+a)x+b(a+2)=12x⇒a2+a=12andb(a+2)=0Soa=−4,3whileb=0Hencef(x)=−4xorf(x)=3x. Commented by Tinkutara last updated on 14/Oct/17 ThankyouverymuchSir! Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 2-e-1-ln-x-1-ln-2-x-dx-Next Next post: A-mass-m-hangs-with-the-help-of-a-string-wrapped-around-a-pulley-on-a-frictionless-bearing-The-pulley-has-mass-m-and-radius-R-Assuming-pulley-to-be-a-perfect-uniform-circular-disc-the-acceleration- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.