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If-f-R-R-is-a-polynomial-function-which-satisfy-the-equation-f-f-x-f-x-12x-x-R-then-find-f-x-




Question Number 22133 by Tinkutara last updated on 11/Oct/17
If f : R^+  → R^+  is a polynomial function  which satisfy the equation f(f(x)) +  f(x) = 12x ∀ x ∈ R^+ , then find f(x).
Iff:R+R+isapolynomialfunctionwhichsatisfytheequationf(f(x))+f(x)=12xxR+,thenfindf(x).
Commented by Rasheed.Sindhi last updated on 22/Oct/17
f( f(x) )+f(x)=12x  Case-1:f(x) is linear  Let f(x)=ax+b   f( f(x) )+f(x)=12x⇒      {a(ax+b)+b}+ax+b=12x    a^2 x+ab+b+ax+b=12x   (a^2 +a)x+ab+2b=12x  Comparing coefficients:    a^2 +a=12 ∧ ab+2b=0  (a−3)(a+4)=0 ∧ b(a+2)=0   (a=3 ∣ a=−4)∧ (b=0 ∣ a=−2)  f(x)=3x, f(x)=−4x   If f(x) is linear then             f(x)=3x or f(x)=−4x
f(f(x))+f(x)=12xCase1:f(x)islinearLetf(x)=ax+bf(f(x))+f(x)=12x{a(ax+b)+b}+ax+b=12xa2x+ab+b+ax+b=12x(a2+a)x+ab+2b=12xComparingcoefficients:a2+a=12ab+2b=0(a3)(a+4)=0b(a+2)=0(a=3a=4)(b=0a=2)f(x)=3x,f(x)=4xIff(x)islinearthenf(x)=3xorf(x)=4x
Answered by ajfour last updated on 14/Oct/17
let f(x)=y  As   f(y)+f(x)=12x  ⇒     (df/dy)×f ′(x)+f ′(x)=12  or   ((df/dy)+1)f ′(x)=12  ⇒(df/dy)=constant & f ′(x)=constant  let f ′(x)=a    , then (df/dy)=((12)/a)−1 ..(i)  ⇒  f ′(x)=ax+b      (..say)         f(y)=ay+b  and    (df/dy)=a   ...(ii)  from (i) and (ii):     a=((12)/a)−1    ⇒  a^2 +a−12=0  ⇒      a=−4 , 3  now   f(y)+f(x)=12x  ⇒     (ay+b)+(ax+b)=12x  ⇒      [a(ax+b)+b]+ax+b=12x  or       (a^2 +a)x+b(a+2)=12x  ⇒    a^2 +a=12   and   b(a+2)=0  So    a=−4 , 3     while b=0       Hence   f(x)=−4x                    or    f(x)=3x .
letf(x)=yAsf(y)+f(x)=12xdfdy×f(x)+f(x)=12or(dfdy+1)f(x)=12dfdy=constant&f(x)=constantletf(x)=a,thendfdy=12a1..(i)f(x)=ax+b(..say)f(y)=ay+banddfdy=a(ii)from(i)and(ii):a=12a1a2+a12=0a=4,3nowf(y)+f(x)=12x(ay+b)+(ax+b)=12x[a(ax+b)+b]+ax+b=12xor(a2+a)x+b(a+2)=12xa2+a=12andb(a+2)=0Soa=4,3whileb=0Hencef(x)=4xorf(x)=3x.
Commented by Tinkutara last updated on 14/Oct/17
Thank you very much Sir!
ThankyouverymuchSir!

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