Question Number 108913 by Rasheed.Sindhi last updated on 20/Aug/20
$$\mathcal{IF}\:{F}\:\:{varies}\:{directly}\:{as}\:{A}\:{and}\:{N}, \\ $$$${find}\:\:{the}\:{constant}\:{of} \\ $$$${proportionality}\:{when}\:{A}=\mathrm{182}, \\ $$$${F}=\mathrm{365}\:{and}\:{N}=\mathrm{80}. \\ $$
Answered by Don08q last updated on 20/Aug/20
$$\:{F}\:=\:{kAN},\:{where}\:{k}\:{is}\:{the}\:{constant} \\ $$$$\:\mathrm{365}\:=\:{k}\left(\mathrm{182}\right)\left(\mathrm{80}\right) \\ $$$$\:{k}\:=\:\frac{\mathrm{365}}{\mathrm{182}×\mathrm{80}} \\ $$$$\:{k}\:=\:\frac{\mathrm{73}}{\mathrm{2912}} \\ $$
Commented by Rasheed.Sindhi last updated on 20/Aug/20
$$\:\mathcal{TH}{anks}\:\mathcal{S}{ir}! \\ $$