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if-f-x-2x-2-12x-10-i-sketch-the-graph-of-y-f-x-for-1-x-7-ii-find-the-set-of-values-of-k-for-which-the-equation-f-x-k-has-4-distinct-roots-




Question Number 113854 by ayenisamuel last updated on 15/Sep/20
if f(x)=2x^2 −12x+10.   (i) sketch the graph of y=∣f(x)∣ for  −1≤x≤7.  (ii) find the set of values of k for  which the equation ∣f(x)∣=k has 4  distinct roots.
iff(x)=2x212x+10.(i)sketchthegraphofy=∣f(x)for1x7.(ii)findthesetofvaluesofkforwhichtheequationf(x)∣=khas4distinctroots.
Answered by MJS_new last updated on 15/Sep/20
∣2x^2 −12x+10∣=k ⇒ k≥0  (2x^2 −12x+10)^2 =k^2   x^4 −12x^3 +46x^2 −60x−(k^2 /4)+25=0  let x=t+3  t^4 −8t^2 −(k^2 /4)+16=0  ⇒ t^2 =((8±k)/2) ⇒ t=±(√((8±k)/2))   [4 solutions]  ⇒ x_(1, 2) =3±(√((8−k)/2)); x_(3, 4) =3±(√((8+k)/2))  ⇒ 4 solutions only if 8−k>0∧8+k>0  ⇒ −8<k<8 but k≥0  ⇒ 0≤k<8
2x212x+10∣=kk0(2x212x+10)2=k2x412x3+46x260xk24+25=0letx=t+3t48t2k24+16=0t2=8±k2t=±8±k2[4solutions]x1,2=3±8k2;x3,4=3±8+k24solutionsonlyif8k>08+k>08<k<8butk00k<8

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