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If-f-x-f-x-1-f-x-1-where-f-10-6-and-f-20-2f-21-then-f-16-




Question Number 154668 by EDWIN88 last updated on 20/Sep/21
 If f(x)=f(x−1)+f(x+1) where  f(10)=6 and f(20)=2f(21)  then f(16)=…?
Iff(x)=f(x1)+f(x+1)wheref(10)=6andf(20)=2f(21)thenf(16)=?
Commented by mathdanisur last updated on 20/Sep/21
f(16) = - f(21)  f(21) = - 6 ⇒ f(16) = 6
f(16)=f(21)f(21)=6f(16)=6
Commented by Rasheed.Sindhi last updated on 20/Sep/21
More details please!
Moredetailsplease!
Answered by Rasheed.Sindhi last updated on 20/Sep/21
f(x)=f(x−1)+f(x+1)  f(x)−f(x−1)=f(x+1)  Applying definition on left side:  f(x)−f(x−1)=f(x)+f(x+2)  f(x−1)=−f(x+2)  x−1→x  f(x)=−f(x+3)  ▶f(10)=−f(13)=6⇒f(13)=−6  ▶f(13)=−f(13+3)=−6                           f(16)=6
f(x)=f(x1)+f(x+1)f(x)f(x1)=f(x+1)Applyingdefinitiononleftside:f(x)f(x1)=f(x)+f(x+2)f(x1)=f(x+2)x1xf(x)=f(x+3)f(10)=f(13)=6f(13)=6f(13)=f(13+3)=6f(16)=6
Commented by mathdanisur last updated on 20/Sep/21
Very nice Ser
VeryniceSer
Commented by Rasheed.Sindhi last updated on 20/Sep/21
Thanks ser!
Thanksser!

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