if-f-x-kx-3-2x-5-is-a-constant-function-then-what-will-be-the-value-of-k-

Question Number 180729 by sciencestudent last updated on 16/Nov/22

i f f (x) = \frac{k x + 3}{2 x - 5} i s a c o n s t a n t f u n c t i o n

t h e n w h a t w i l l b e t h e v a l u e o f k ?

Answered by srikanth2684 last updated on 16/Nov/22

f^{'} (x) = 0

\frac{k (- 5) - (3) (2)}{{(2 x - 5)}^{2}} = 0

- 6 = 5 k

\frac{- 6}{5} = k

Answered by mr W last updated on 16/Nov/22

\frac{k x + 3}{2 x - 5} = c

(k - 2 c) x + 3 + 5 c = 0

3 + 5 c = 0 \Rightarrow c = - \frac{3}{5}

k - 2 c = 0 \Rightarrow k = - \frac{6}{5}

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