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Question Number 46570 by scientist last updated on 28/Oct/18
If in triangle ABC   ((cosB)/b) =((cosC)/c), show that the  triangle is isosceles
IfintriangleABCcosBb=cosCc,showthatthetriangleisisosceles
Answered by tanmay.chaudhury50@gmail.com last updated on 28/Oct/18
((sinA)/a)=((sinB)/b)=((sinC)/c)  ((cosB)/(cosC))=((sinB)/(sinC))=(b/c)  sinBcosC−sinCcosB=0  sin(B−C)=0   so B−C=0  ∠B=∠C   proved
sinAa=sinBb=sinCccosBcosC=sinBsinC=bcsinBcosCsinCcosB=0sin(BC)=0soBC=0B=Cproved

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