If-lim-x-0-cos-m-mx-cos-n-nx-m-2-n-2-mn-x-2-1-find-m-2-n-2-4-mn- Tinku Tara June 4, 2023 Limits 0 Comments FacebookTweetPin Question Number 168576 by cortano1 last updated on 13/Apr/22 Iflimx→0cosm(mx)−cosn(nx)(m2+n2+mn)x2=1findm2+n2−4mn. Commented by blackmamba last updated on 17/Apr/22 m2+n2+mn=limx→0cosm(mx)−cosn(nx)x2m2+n2+mn=n3−m32n3−m3(n−m)=n3−m32(n3−m3)(1n−m−12)=0n−m=2⇒n2−2mn+m2=4⇒m2+n2−4=2mn⇒m2+n2−4mn=2 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: given-5x-12y-60-min-value-of-x-2-y-2-Next Next post: find-the-product-of-roots-2021-1-3-x-log-2021-x-x-3- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.