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If-log-12-27-a-express-log-6-16-in-terms-of-a-




Question Number 113811 by Aina Samuel Temidayo last updated on 15/Sep/20
If log_(12) 27=a, express log_6 16 in terms  of a.
Iflog1227=a,expresslog616intermsofa.
Answered by bemath last updated on 15/Sep/20
((ln 27)/(ln 12)) = a ⇒((3ln 3)/a) = ln 12  ((3ln 3)/a) = ln 3+2ln 2 → 2ln 2=((3ln 3)/a)−ln 3  ⇔ ((ln 16)/(ln 6)) = ((4ln 2)/(ln 2+ln 3)) = (((2(3−a)ln 3)/a)/((((3−a)ln 3)/(2a))+ln 3))  = (((6−2a)/a)/((3−a+2a)/(2a))) = ((6−2a)/a) ×((2a)/(3+a)) = ((12−4a)/(3+a))
ln27ln12=a3ln3a=ln123ln3a=ln3+2ln22ln2=3ln3aln3ln16ln6=4ln2ln2+ln3=2(3a)ln3a(3a)ln32a+ln3=62aa3a+2a2a=62aa×2a3+a=124a3+a
Commented by Aina Samuel Temidayo last updated on 15/Sep/20
=((4(3−a))/(3+a))    Thanks.
=4(3a)3+aThanks.

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