If-log-12-27-a-express-log-6-16-in-terms-of-a- Tinku Tara June 4, 2023 Logarithms 0 Comments FacebookTweetPin Question Number 113811 by Aina Samuel Temidayo last updated on 15/Sep/20 Iflog1227=a,expresslog616intermsofa. Answered by bemath last updated on 15/Sep/20 ln27ln12=a⇒3ln3a=ln123ln3a=ln3+2ln2→2ln2=3ln3a−ln3⇔ln16ln6=4ln2ln2+ln3=2(3−a)ln3a(3−a)ln32a+ln3=6−2aa3−a+2a2a=6−2aa×2a3+a=12−4a3+a Commented by Aina Samuel Temidayo last updated on 15/Sep/20 =4(3−a)3+aThanks. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: z-5-32-find-all-root-z-Next Next post: lim-x-0-xlnx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.