If-log-logx-3log-logx-log-log-logx-27-Find-x-

Question Number 151013 by mathdanisur last updated on 17/Aug/21

If \log {(\log x)}^{\frac{3 \log (logx)}{\log (\log (logx))}} = 27

Find x = ?

Answered by Olaf_Thorendsen last updated on 17/Aug/21

\log {(\log x)}^{\frac{3 \log (\log x)}{\log (\log (\log x))}} = 27 = 3^{3}

\frac{3 \log (\log x)}{\log (\log (\log x))} \log (\log (\log x)) = 3 \log 3

3 \log (\log x) = 3 \log 3

\log x = 3

x = e^{3}

Commented by mathdanisur last updated on 17/Aug/21

Thank you Ser

Commented by Olaf_Thorendsen last updated on 17/Aug/21

In my country we write

\ln e^{x} = x and {\log 10}^{x} = x

But in some other countries they write

\log e^{x} = x and {Log 10}^{x} = x