Menu Close

If-log-tan-1-log-tan-2-log-tan-3-log-tan-89-p-then-p-2-3-




Question Number 115341 by bemath last updated on 25/Sep/20
If log tan 1°+log tan 2°+log tan 3°+...+log tan 89°=p  then p^2 +3 =
Iflogtan1°+logtan2°+logtan3°++logtan89°=pthenp2+3=
Answered by bobhans last updated on 25/Sep/20
⇒log (tan 1°×tan 2°×tan 3°×...×tan 89°)=p  consider tan 89°×tan 1°=1  tan 88°×tan 2°=1 , so on . we get   log (1×1×1×1×...×1) = p  ⇒p = 0 then p^2 +3 = 3
log(tan1°×tan2°×tan3°××tan89°)=pconsidertan89°×tan1°=1tan88°×tan2°=1,soon.wegetlog(1×1×1×1××1)=pp=0thenp2+3=3

Leave a Reply

Your email address will not be published. Required fields are marked *