Question Number 83037 by otchereabdullai@gmail.com last updated on 27/Feb/20
$$\mathrm{If}\:\mathrm{m}=\frac{\mathrm{1}−\mathrm{cos}\theta}{\mathrm{sin}\theta}\:,\:\:\mathrm{show}\:\mathrm{that}\:\frac{\mathrm{1}}{\mathrm{m}}=\:\frac{\mathrm{1}+\mathrm{sin}\theta}{\mathrm{sin}\theta} \\ $$
Commented by Tony Lin last updated on 27/Feb/20
$$\frac{\mathrm{1}}{{m}}=\frac{{sin}\theta}{\mathrm{1}−{cos}\theta}=\:\frac{{sin}\theta\left(\mathrm{1}+{cos}\theta\right)}{\left(\mathrm{1}−{cos}\theta\right)\left(\mathrm{1}+{cos}\theta\right)} \\ $$$$=\frac{\mathrm{1}+{cos}\theta}{{sin}\theta} \\ $$
Commented by otchereabdullai@gmail.com last updated on 27/Feb/20
$$\mathrm{thanks}\:\mathrm{sir}\:\mathrm{tony} \\ $$
Commented by JDamian last updated on 27/Feb/20
$${Really}? \\ $$