If-m-1-n-3-then-find-the-value-of-1-2-m-3-6m-2-12m-8-n-n-

Question Number 191546 by MATHEMATICSAM last updated on 25/Apr/23

If m + 1 = \sqrt{n} + 3 then find the value of

\frac{1}{2} (\frac{m^{3} - 6 m^{2} + 12 m - 8}{\sqrt{n}} - n)

Answered by som(math1967) last updated on 25/Apr/23

\frac{1}{2} \times {\frac{{(m - 2)}^{3}}{\sqrt{n}} - n}

\frac{1}{2} \times {\frac{{(\sqrt{n})}^{3}}{\sqrt{n}} - n} [m + 1 = \sqrt{n} + 3 \Rightarrow m - 2 = \sqrt{n}]

\frac{1}{2} \times (n - n) = 0