Menu Close

If-m-n-N-n-gt-m-then-number-of-solutions-of-the-equation-n-sin-x-m-sin-x-in-0-2pi-is-




Question Number 17153 by Tinkutara last updated on 01/Jul/17
If m, n ∈ N(n > m), then number of  solutions of the equation  n∣sin x∣ = m∣sin x∣ in [0, 2π] is
Ifm,nN(n>m),thennumberofsolutionsoftheequationnsinx=msinxin[0,2π]is
Answered by mrW1 last updated on 01/Jul/17
n∣sin x∣ = m∣sin x∣  ∵ m≠n  ∴ ∣sin x∣=0  x=0,π,2π  ⇒there are 3 solutions
nsinx=msinxmnsinx∣=0x=0,π,2πthereare3solutions
Commented by Tinkutara last updated on 02/Jul/17
Thanks Sir!
ThanksSir!

Leave a Reply

Your email address will not be published. Required fields are marked *