If-n-gt-m-then-a-m-a-n-a-

Question Number 126206 by amns last updated on 18/Dec/20

I f (n > m),

then \frac{a^{m}}{a^{n}} = a^{?}

Commented by amns last updated on 18/Dec/20

Is the ans . a^{\frac{1}{n - m}} ?

Answered by MJS_new last updated on 18/Dec/20

\frac{a^{m}}{a^{n}} = a^{m - n}

no matter if m > n or m < n

a^{- k} = \frac{1}{a^{k}} \Rightarrow a^{m - n} = \frac{1}{a^{n - m}}

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