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If-n-j-k-prove-or-disprove-d-n-dx-n-f-x-d-j-dx-j-d-k-dx-k-f-x-d-k-dx-k-d-j-dx-j-f-x-




Question Number 165044 by alephzero last updated on 25/Jan/22
If n = j + k, prove or disprove  (d^n /dx^n )f(x) = (d^j /dx^j )((d^k /dx^k )f(x)) = (d^k /dx^k )((d^j /dx^j )f(x))
$$\mathrm{If}\:{n}\:=\:{j}\:+\:{k},\:\mathrm{prove}\:\mathrm{or}\:\mathrm{disprove} \\ $$$$\frac{{d}^{{n}} }{{dx}^{{n}} }{f}\left({x}\right)\:=\:\frac{{d}^{{j}} }{{dx}^{{j}} }\left(\frac{{d}^{{k}} }{{dx}^{{k}} }{f}\left({x}\right)\right)\:=\:\frac{{d}^{{k}} }{{dx}^{{k}} }\left(\frac{{d}^{{j}} }{{dx}^{{j}} }{f}\left({x}\right)\right) \\ $$
Commented by mr W last updated on 25/Jan/22
this is the same as  n=j+k=k+j  y^((n))  means doing n times derivative,  like eating n apples. you can do k  times and then j times, or you do j  times and then k times. just like  you eat k apples at first and then j   apples, it′s the same as you eat j apples   at first and then k apples.
$${this}\:{is}\:{the}\:{same}\:{as} \\ $$$${n}={j}+{k}={k}+{j} \\ $$$${y}^{\left({n}\right)} \:{means}\:{doing}\:{n}\:{times}\:{derivative}, \\ $$$${like}\:{eating}\:{n}\:{apples}.\:{you}\:{can}\:{do}\:{k} \\ $$$${times}\:{and}\:{then}\:{j}\:{times},\:{or}\:{you}\:{do}\:{j} \\ $$$${times}\:{and}\:{then}\:{k}\:{times}.\:{just}\:{like} \\ $$$${you}\:{eat}\:{k}\:{apples}\:{at}\:{first}\:{and}\:{then}\:{j}\: \\ $$$${apples},\:{it}'{s}\:{the}\:{same}\:{as}\:{you}\:{eat}\:{j}\:{apples}\: \\ $$$${at}\:{first}\:{and}\:{then}\:{k}\:{apples}. \\ $$
Commented by alephzero last updated on 25/Jan/22
Thank you, mr W
$$\mathrm{Thank}\:\mathrm{you},\:\mathrm{mr}\:\boldsymbol{\mathcal{W}} \\ $$

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