If-p-is-the-measure-of-per-pendicular-segment-from-the-origin-on-the-line-whose-intercept-are-a-and-b-show-that-1-a-2-1-b-2-1-p-2-

Question Number 54364 by peter frank last updated on 02/Feb/19

If p is the measure of per

pendicular segment from

the origin on the line

whose intercept are

a and b . show that

\frac{1}{a^{2}} + \frac{1}{b^{2}} = \frac{1}{p^{2}}

Answered by tanmay.chaudhury50@gmail.com last updated on 03/Feb/19

e q n s t l i n e \frac{x}{a} + \frac{y}{b} = 1

∣ \frac{\frac{0}{a} + \frac{0}{b} - 1}{\sqrt{{(\frac{1}{a})}^{2} + {(\frac{1}{b})}^{2}}} ∣= p

\frac{1}{\frac{1}{a^{2}} + \frac{1}{b^{2}}} = p^{2}

\frac{1}{a^{2}} + \frac{1}{b^{2}} = \frac{1}{p^{2}}

Commented by peter frank last updated on 03/Feb/19

thank you mr tanmay