If-P-RE-2-R-B-2-make-R-the-subject-of-the-formula-

Question Number 89153 by Jidda28 last updated on 15/Apr/20

If P = \frac{{RE}^{2}}{{(R + B)}^{2}} make R the subject of the formula .

Answered by MJS last updated on 15/Apr/20

p {(r + b)}^{2} = {r e}^{2}

{(r + b)}^{2} = \frac{e^{2}}{p} r

r^{2} + (2 b - \frac{e^{2}}{p}) r + b^{2} = 0

r = \frac{e^{2}}{2 p} - b \pm \sqrt{{(b - \frac{e^{2}}{2 p})}^{2} - b^{2}}

r = \frac{e^{2}}{2 p} - b \pm \frac{e}{2 p} \sqrt{e^{2} - 4 b p}

Commented by Jidda28 last updated on 15/Apr/20

thank you sir

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