If-sin-1-sin-1-pi-2-2-2-

Question Number 100133 by bemath last updated on 25/Jun/20

If \sin^{- 1} θ + \sin^{- 1} β = π

θ + β - \frac{2}{θ^{2} + β^{2}} = ?

Answered by smridha last updated on 25/Jun/20

\sin^{- 1} (θ) = \frac{π}{2} + \frac{π}{2} - \sin^{- 1} (β)

\sin^{- 1} (θ) = \frac{π}{2} + \cos^{- 1} (β)

θ = s i n (\frac{π}{2} + \cos^{- 1} (β)) = c o s (\cos^{- 1} (β))

s o θ = β

n o w θ + β - \frac{2}{θ^{2} + β^{2}} = 2 θ - \frac{1}{2 θ^{2}}

o r 2 β - \frac{1}{2 β^{2}} .

Commented by bemath last updated on 25/Jun/20

thank you Mister

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