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if-sin-x-x-20-20-find-x-




Question Number 61162 by Tawa1 last updated on 29/May/19
if     sin(x)  =  ((x − 20)/(20))  ,   find  x
ifsin(x)=x2020,findx
Commented by kaivan.ahmadi last updated on 29/May/19
we can find number of solution by plote  y=sinx and y=((x−20)/(20))  this equation has 13 answer
wecanfindnumberofsolutionbyplotey=sinxandy=x2020thisequationhas13answer
Commented by maxmathsup by imad last updated on 29/May/19
(e) ⇔sin(x) =(x/(20)) −1  changement (x/(20)) =t give  sin(20t) =t−1 ⇔ sin(20t)−t +1 =0  let f(t) =sin(20t)−t+1 ⇒f^′ (t) =20cos(t)−1  f^′ (t) =0 ⇒20cost =1 ⇔cost =(1/(20)) let α /cos(α)=(1/(20)) ⇒  t =α +2kπ  or t =−α +2kπ ⇒t =arcos((1/(20)))+2kπ or   t =−arcos((1/(20))) +2kπ   in this case it better to use  newton  method  to approximate the roots....
(e)sin(x)=x201changementx20=tgivesin(20t)=t1sin(20t)t+1=0letf(t)=sin(20t)t+1f(t)=20cos(t)1f(t)=020cost=1cost=120letα/cos(α)=120t=α+2kπort=α+2kπt=arcos(120)+2kπort=arcos(120)+2kπinthiscaseitbettertousenewtonmethodtoapproximatetheroots.
Commented by Tawa1 last updated on 30/May/19
God bless you sir
Godblessyousir
Answered by malwaan last updated on 29/May/19
−1≤sin(x)≤1  ⇒−1≤((x−20)/(20))≤1  ⇒−20≤x−20≤20  ⇒0≤ x≤40  ⇒x∈[ 0 ; 40]
1sin(x)11x2020120x20200x40x[0;40]
Commented by Tawa1 last updated on 30/May/19
God bless you sir
Godblessyousir

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