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If-T-2pi-L-g-1-2-and-L-100-0-1-cm-limit-standard-error-T-2-01-0-01-s-limit-standard-error-Calculate-the-value-of-g-and-its-standard-error-




Question Number 28929 by NECx last updated on 01/Feb/18
If T=2π((L/g))^(1/(2 ))  and  L=100±0.1 cm(limit standard   error)  T=2.01±0.01 s (limit standard  error)  Calculate the value of g and its  standard error.
IfT=2π(Lg)12andL=100±0.1cm(limitstandarderror)T=2.01±0.01s(limitstandarderror)Calculatethevalueofganditsstandarderror.
Answered by Tinkutara last updated on 02/Feb/18
g=((4π^2 L)/T^2 )  L=1±10^(−3)  m  T=2.01±0.01 s  g≈9.77 m/s^2   ((Δg)/g)=((ΔL)/L)+((2ΔT)/T)  Δg=9.77(((10^(−3) )/1)+((2×0.01)/(2.01)))≈0.107  ⇒g=9.77±0.107 m/s^2
g=4π2LT2L=1±103mT=2.01±0.01sg9.77m/s2Δgg=ΔLL+2ΔTTΔg=9.77(1031+2×0.012.01)0.107g=9.77±0.107m/s2
Commented by NECx last updated on 03/Feb/18
wow... Thanks
wowThanks
Commented by NECx last updated on 08/Feb/18
i think this was for maximum  error.
ithinkthiswasformaximumerror.

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