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Question Number 149309 by ArielVyny last updated on 04/Aug/21
if    t=tanx what is the value of  sinx and cosx ?
ift=tanxwhatisthevalueofsinxandcosx?
Answered by nimnim last updated on 04/Aug/21
sinx=(t/( (√(1+t^2 )))),  cosx=(1/( (√(1+t^2 ))))
sinx=t1+t2,cosx=11+t2
Answered by puissant last updated on 04/Aug/21
sin(x)=((∣t∣)/( (√(1+t^2 ))))  ;  cos(x)=(1/( (√(1+t^2 ))))..
sin(x)=t1+t2;cos(x)=11+t2..
Answered by mathmax by abdo last updated on 04/Aug/21
cos^2 x =(1/(1+tan^2 x))=(1/(1+t^2 )) ⇒cos(x)=+^−  (1/( (√(1+t^2 ))))  sin^2 x=1−cos^2 x =1−(1/(1+t^2 ))=(t^2 /(1+t^2 )) ⇒sinx =((∣t∣)/( (√(1+t^2 ))))
cos2x=11+tan2x=11+t2cos(x)=+11+t2sin2x=1cos2x=111+t2=t21+t2sinx=t1+t2

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