Question Number 43889 by SNILL JAMES last updated on 17/Sep/18
$${if}\:{tan}\:{A}\:+\:{tan}\:{B}=\mathrm{90} \\ $$$${find}\:{taAtanB} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 17/Sep/18
$${tan}\left({A}+{B}\right)=\frac{{tanA}+{tanB}}{\mathrm{1}−{tanAtanB}} \\ $$$$\mathrm{1}−{tanAtanB}=\frac{\mathrm{90}}{{tan}\left({A}+{B}\right)} \\ $$$${tanAtanB}=\mathrm{1}−\frac{\mathrm{90}}{{tan}\left({A}+{B}\right)} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$