Question Number 54093 by Tawa1 last updated on 28/Jan/19

Commented by mr W last updated on 28/Jan/19

Commented by Tawa1 last updated on 29/Jan/19

Commented by mr W last updated on 29/Jan/19
![z=x+y i tan z=((sin (2x)+i sinh (2y))/(cosh (2y)+cos (2x)))=2 sinh (2y)=0⇒y=0 sin (2x)=2 [cosh (2y)+cos (2x)] 2 sin x cos x=2 [1+2cos^2 x−1] sin x=2cos x tan x=2⇒x=tan^(−1) 2+nπ ⇒z=tan^(−1) 2+nπ+0i](https://www.tinkutara.com/question/Q54108.png)
Commented by Tawa1 last updated on 29/Jan/19

Commented by Tawa1 last updated on 29/Jan/19

Commented by Tawa1 last updated on 29/Jan/19

Commented by mr W last updated on 29/Jan/19

Commented by Tawa1 last updated on 29/Jan/19
