If-the-roots-and-of-the-equation-ax-2-bx-c-0-are-real-and-of-opposite-sign-then-the-roots-of-the-equation-x-2-x-2-is-are-1-Positive-2-Negative-3-Real-and-opposite-si Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 20052 by Tinkutara last updated on 21/Aug/17 Iftherootsαandβoftheequationax2+bx+c=0arerealandofoppositesignthentherootsoftheequationα(x−β)2+β(x−α)2is/are(1)Positive(2)Negative(3)Realandoppositesign(4)Imaginary Answered by ajfour last updated on 21/Aug/17 givenαβ<0secondequationreformedis(α+β)x2−4αβx+αβ(α+β)=0D=16α2β2−4αβ(α+β)2>0forαβ<0Hencerootsofsecondequationγ,δarereal.γδ=CA=αβ(α+β)α+β=αβ<0Henceγandδhaveoppositesigns.(3)isthecorrectoption. Commented by Tinkutara last updated on 21/Aug/17 ThankyouverymuchSir! Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: If-x-R-then-x-2-2x-a-x-2-4x-3a-can-take-all-real-values-if-1-a-0-2-2-a-0-1-3-a-1-1-4-None-of-these-Next Next post: Question-85588 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.