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If-the-roots-and-of-the-equation-ax-2-bx-c-0-are-real-and-of-opposite-sign-then-the-roots-of-the-equation-x-2-x-2-is-are-1-Positive-2-Negative-3-Real-and-opposite-si




Question Number 20052 by Tinkutara last updated on 21/Aug/17
If the roots α and β of the equation  ax^2  + bx + c = 0 are real and of opposite  sign then the roots of the equation  α(x − β)^2  + β(x − α)^2  is/are  (1) Positive  (2) Negative  (3) Real and opposite sign  (4) Imaginary
Iftherootsαandβoftheequationax2+bx+c=0arerealandofoppositesignthentherootsoftheequationα(xβ)2+β(xα)2is/are(1)Positive(2)Negative(3)Realandoppositesign(4)Imaginary
Answered by ajfour last updated on 21/Aug/17
  given   αβ < 0  second equation reformed is  (α+β)x^2 −4αβx+αβ(α+β)=0  D=16α^2 β^2 −4αβ(α+β)^2  >0  for αβ < 0   Hence roots of second equation       γ, δ are real.      γδ=(C/A)=((αβ(α+β))/(α+β)) = αβ < 0  Hence γ and δ have opposite signs .  (3) is the correct option .
givenαβ<0secondequationreformedis(α+β)x24αβx+αβ(α+β)=0D=16α2β24αβ(α+β)2>0forαβ<0Hencerootsofsecondequationγ,δarereal.γδ=CA=αβ(α+β)α+β=αβ<0Henceγandδhaveoppositesigns.(3)isthecorrectoption.
Commented by Tinkutara last updated on 21/Aug/17
Thank you very much Sir!
ThankyouverymuchSir!

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