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Question Number 160123 by mr W last updated on 24/Nov/21
if we write all natural numbers  together like this  1234567891011121314151617...,  what is the 1000th digit?
$${if}\:{we}\:{write}\:{all}\:{natural}\:{numbers} \\ $$$${together}\:{like}\:{this} \\ $$$$\mathrm{1234567891011121314151617}…, \\ $$$${what}\:{is}\:{the}\:\mathrm{1000}{th}\:{digit}? \\ $$
Answered by nikif99 last updated on 24/Nov/21
1−9: 9 numbers×1 digit=9 digits  10−99: 90×2=180  100−369: 270 numbers×3 digits=810  ⇒1−369: 999 digits  1000th digit: 3
$$\mathrm{1}−\mathrm{9}:\:\mathrm{9}\:{numbers}×\mathrm{1}\:{digit}=\mathrm{9}\:{digits} \\ $$$$\mathrm{10}−\mathrm{99}:\:\mathrm{90}×\mathrm{2}=\mathrm{180} \\ $$$$\mathrm{100}−\mathrm{369}:\:\mathrm{270}\:{numbers}×\mathrm{3}\:{digits}=\mathrm{810} \\ $$$$\Rightarrow\mathrm{1}−\mathrm{369}:\:\mathrm{999}\:{digits} \\ $$$$\mathrm{1000}{th}\:{digit}:\:\mathrm{3} \\ $$
Commented by mr W last updated on 24/Nov/21
thanks!
$${thanks}! \\ $$
Answered by puissant last updated on 24/Nov/21
1−9 : 9 numbers ×1 digit = 9 digits  10−99 : (99−9)×2 digits = 180 digits  100−999 : (999−99)×3 digits = 2700 digits  (1000−9−180)=(1000−189)=811  E(((811)/3))+100 = 370.. 1000th digit : 3                     ...........Le puissant.........
$$\mathrm{1}−\mathrm{9}\::\:\mathrm{9}\:{numbers}\:×\mathrm{1}\:{digit}\:=\:\mathrm{9}\:{digits} \\ $$$$\mathrm{10}−\mathrm{99}\::\:\left(\mathrm{99}−\mathrm{9}\right)×\mathrm{2}\:{digits}\:=\:\mathrm{180}\:{digits} \\ $$$$\mathrm{100}−\mathrm{999}\::\:\left(\mathrm{999}−\mathrm{99}\right)×\mathrm{3}\:{digits}\:=\:\mathrm{2700}\:{digits} \\ $$$$\left(\mathrm{1000}−\mathrm{9}−\mathrm{180}\right)=\left(\mathrm{1000}−\mathrm{189}\right)=\mathrm{811} \\ $$$${E}\left(\frac{\mathrm{811}}{\mathrm{3}}\right)+\mathrm{100}\:=\:\mathrm{370}..\:\mathrm{1000}{th}\:{digit}\::\:\mathrm{3} \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:………..\mathscr{L}{e}\:{puissant}……… \\ $$
Commented by mr W last updated on 24/Nov/21
thanks!
$${thanks}! \\ $$

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