Question Number 175399 by Engr_Jidda last updated on 29/Aug/22
$${if}\:\left({x}+\mathrm{1}\right)^{\mathrm{4}} \sqrt{\mathrm{4}}={x}+\mathrm{1}\:\:{find}\:{x} \\ $$
Commented by Frix last updated on 29/Aug/22
$$\left({x}+\mathrm{1}\right)^{\mathrm{4}} ×\sqrt{\mathrm{4}}\:\mathrm{or}\:\left({x}+\mathrm{1}\right)×\sqrt[{\mathrm{4}}]{\mathrm{4}}? \\ $$
Commented by Engr_Jidda last updated on 29/Aug/22
$$\left({x}+\mathrm{1}\right)×\mathrm{4}\sqrt{\mathrm{4}} \\ $$
Commented by Ar Brandon last updated on 29/Aug/22
$${x}=−\mathrm{1} \\ $$