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if-x-2-1-3-2-1-3-2-x-2-1-3-1-3-2-then-find-the-value-of-198x-4-868x-3-229x-2-200x-




Question Number 152772 by Rankut last updated on 01/Sep/21
if  ((((x−2))^(1/3) +2))^(1/3)  + ((2−((x−2))^(1/3) ))^(1/3) =2   then  find the value of   (√(198x^4 −868x^3 −229x^2 +200x))
ifx23+23+2x233=2thenfindthevalueof198x4868x3229x2+200x
Commented by Rankut last updated on 01/Sep/21
any help please
anyhelpplease
Commented by MJS_new last updated on 01/Sep/21
typo?  there′s a similae question... just scroll down  to find it
typo?theresasimilaequestionjustscrolldowntofindit
Answered by mr W last updated on 01/Sep/21
let t=((x−2))^(1/3)   ((2+t))^(1/3) +((2−t))^(1/3) =2  2+t+2−t+3×2((4−t^2 ))^(1/3) =8  3((4−t^2 ))^(1/3) =2  27(4−t^2 )=8  t=±(√(4−(8/(27))))=±((10(√3))/9)  x=2+t^3 =2±((1000(√3))/(243))  ......
lett=x232+t3+2t3=22+t+2t+3×24t23=834t23=227(4t2)=8t=±4827=±1039x=2+t3=2±10003243
Commented by Rankut last updated on 01/Sep/21
thank you sir
thankyousir

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