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if-x-2-11x-5-x-2-x-30-then-faind-x-2-x-3-

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Question Number 172704 by mathlove last updated on 30/Jun/22
if (x^2 +11x)+(5/((x^2 −x)))=−30 then faind:(x+2)(x+3)=?
if(x2+11x)+5(x2−x)=−30thenfaind:(x+2)(x+3)=?
Answered by mahdipoor last updated on 30/Jun/22
⇒x≠0,1 & A=(x+2)(x+3)=x^2 +5x+6 ; ⇒(x^2 −x)(x^2 +11x)+5=−30(x^2 −x) ⇒(x^2 −x)(x^2 +11x+30)=−5 ⇒[x(x+5)].[(x−1)(x+6)]=−5= (x^2 +5x)(x^2 +5x−6)=(A−6)(A−12) ⇒ A=11 or 7
⇒x≠0,1&A=(x+2)(x+3)=x2+5x+6;⇒(x2−x)(x2+11x)+5=−30(x2−x)⇒(x2−x)(x2+11x+30)=−5⇒[x(x+5)].[(x−1)(x+6)]=−5=(x2+5x)(x2+5x−6)=(A−6)(A−12)⇒A=11or7
Commented by mathlove last updated on 30/Jun/22
thanks
thanks

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