Question Number 119193 by mr W last updated on 22/Oct/20

Commented by PRITHWISH SEN 2 last updated on 22/Oct/20

Commented by mr W last updated on 22/Oct/20

Commented by PRITHWISH SEN 2 last updated on 22/Oct/20

Answered by TANMAY PANACEA last updated on 22/Oct/20

Commented by mr W last updated on 22/Oct/20

Commented by TANMAY PANACEA last updated on 22/Oct/20

Answered by 1549442205PVT last updated on 23/Oct/20
![x^3 +(1/x^3 )=52⇔x^6 −52x^3 +1=0 Δ′=26^2 −1=675=(15(√3))^2 ⇒x^3 =26±15(√3) =(2±(√3) )^3 ⇒x=2±(√3) Since (2+(√3))(2−(√3))=1⇒x+(1/x) =2+(√3)+2−(√3)=4 ⇒(x^4 +(1/x^4 ))=(x^2 +(1/x^2 ))−2=[(x+(1/x))^2 −2]^2 −2 =(4^2 −2)^2 −2=14^2 −2=194](https://www.tinkutara.com/question/Q119232.png)
Answered by malwan last updated on 24/Oct/20
