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if-x-gt-0-r-pq-1-p-q-then-1-rx-1-qx-p-1-px-q-1-x-r-




Question Number 144095 by mathdanisur last updated on 21/Jun/21
if  x>0 , r=pq , 1≤p≤q  then:  1+rx ≤ (1+qx)^p  ≤ (1+px)^q  ≤ (1+x)^r
ifx>0,r=pq,1pqthen:1+rx(1+qx)p(1+px)q(1+x)r
Answered by mitica last updated on 21/Jun/21
(1+x)^r =[(1+x)^p ]^q  ≥^(bernoulli) (1+px)^q   (1+qx)^p  ≥^(bernoulli) 1+pqx=1+rx  f(t)=((ln(1+t))/t) ↘  px≤qx⇒((ln(1+px))/p)≥((ln(1+qx))/q)⇒(1+px)^q ≥(1+qx)^p
(1+x)r=[(1+x)p]qbernoulli(1+px)q(1+qx)pbernoulli1+pqx=1+rxf(t)=ln(1+t)t↘pxqxln(1+px)pln(1+qx)q(1+px)q(1+qx)p
Commented by mathdanisur last updated on 21/Jun/21
alot perfect Sir thank you
alotperfectSirthankyou

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