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if-x-is-a-selected-number-of-the-number-from-20-99-then-what-is-probalility-x-3-x-is-divided-by-12-




Question Number 98773 by john santu last updated on 16/Jun/20
if x is a selected number of the  number from 20−99, then what  is probalility x^3 −x is divided by  12?
ifxisaselectednumberofthenumberfrom2099,thenwhatisprobalilityx3xisdividedby12?
Answered by mr W last updated on 16/Jun/20
x^3 −x=(x−1)x(x+1)  x−1=12k ⇒x=12k+1, k=2..8  x=12k ⇒x=12k, k=2..8  x+1=12k ⇒x=12k−1, k=2..8  3×7=21 possible values for x  ⇒p=((21)/(80))
x3x=(x1)x(x+1)x1=12kx=12k+1,k=2..8x=12kx=12k,k=2..8x+1=12kx=12k1,k=2..83×7=21possiblevaluesforxp=2180
Commented by mr W last updated on 16/Jun/20
you are right sir!  p=((60)/(80))=(3/4)
youarerightsir!p=6080=34
Commented by mr W last updated on 16/Jun/20
case 1: x−1 is even, i.e. x is odd,  i.e. x=21, 23, ..., 99 ⇒ 40 numbers  case 2: x is divisible by 4,  i.e. x=20, 24, ..., 96 ⇒ 20 numbers  ⇒totally 60 values for x.
case1:x1iseven,i.e.xisodd,i.e.x=21,23,,9940numberscase2:xisdivisibleby4,i.e.x=20,24,,9620numberstotally60valuesforx.
Commented by john santu last updated on 16/Jun/20
yes. thank you friend
yes.thankyoufriend
Commented by MJS last updated on 16/Jun/20
x^3 −x is always divisible by 3  thus we only need to check which numbers  are divisible by 4
x3xisalwaysdivisibleby3thusweonlyneedtocheckwhichnumbersaredivisibleby4
Answered by MJS last updated on 16/Jun/20
n=x^3 −x=x(x−1)(x+1)  ⇒ 3∣n ∀x∈Z  ⇒  { ((x=2k+1 ⇒ 12∣n)),((x=2n ⇒  { ((x=4n ⇒ 12∣n)),((x=4n+2 ⇒ 12∤n)) :})) :}  ⇒ for 20≤x≤99 we have 20 numbers for  which 12∤n  ⇒ searched probability is (3/4)
n=x3x=x(x1)(x+1)3nxZ{x=2k+112nx=2n{x=4n12nx=4n+212nfor20x99wehave20numbersforwhich12nsearchedprobabilityis34
Commented by john santu last updated on 16/Jun/20
why the method mr W not same sir.  i got too((21)/(80))
whythemethodmrWnotsamesir.igottoo2180
Commented by MJS last updated on 16/Jun/20
n=x(x−1)(x+1)  x     n  20   12×665  21   12×770  22   10626  23   12×1012  24   12×1150  25   12×1300  26   17550  27   12×1638  28   12×1827  29   12×2030  ...
n=x(x1)(x+1)xn2012×6652112×77022106262312×10122412×11502512×130026175502712×16382812×18272912×2030
Commented by bemath last updated on 16/Jun/20
for x =22 , 26 , ... not satisfy sir
forx=22,26,notsatisfysir
Commented by bemath last updated on 16/Jun/20
30   30×29×31 ∤ 12  34    34×33×35 ∤12  38    38×37×39 ∤ 12  correct sir?
3030×29×31123434×33×35123838×37×3912correctsir?
Commented by MJS last updated on 16/Jun/20
yes
yes
Commented by john santu last updated on 16/Jun/20
thank you sir
thankyousir

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