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If-x-iy-1-a-ib-prove-that-x-2-y-2-a-2-b-2-1-




Question Number 16917 by tawa tawa last updated on 28/Jun/17
If   x + iy = (1/(a + ib))  prove that :   (x^2  + y^2 )(a^2  + b^2 ) = 1
Ifx+iy=1a+ibprovethat:(x2+y2)(a2+b2)=1
Answered by Tinkutara last updated on 28/Jun/17
x + iy = (1/(a + ib))  x − iy = (1/(a − ib))  x^2  + y^2  = (1/(a^2  + b^2 ))
x+iy=1a+ibxiy=1aibx2+y2=1a2+b2
Commented by tawa tawa last updated on 28/Jun/17
God bless you sir. but sir why   (x − iy) = (1/((a − ib)))
Godblessyousir.butsirwhy(xiy)=1(aib)
Commented by Tinkutara last updated on 28/Jun/17
It is a rule for complex numbers: If  z = (z_1 /z_2 ) then z^�  = (z_1 ^� /z_2 ^� ), where z^�  denotes  the conjugate of z.
Itisaruleforcomplexnumbers:Ifz=z1z2thenz¯=z¯1z¯2,wherez¯denotestheconjugateofz.
Commented by tawa tawa last updated on 28/Jun/17
God bless you sir.
Godblessyousir.

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