Question Number 49640 by maxmathsup by imad last updated on 08/Dec/18
![if x ∈[p,(√(p^2 +2))] calculate [x]](https://www.tinkutara.com/question/Q49640.png)
Commented by maxmathsup by imad last updated on 08/Dec/18

Commented by Abdo msup. last updated on 23/Dec/18
![we have p≤x≤(√(p^2 +2))≤p+1 ⇒[x]=p](https://www.tinkutara.com/question/Q50982.png)
Answered by tanmay.chaudhury50@gmail.com last updated on 09/Dec/18
![consider p=+ve integer p=I (√(p^2 +2)) =I+f when x lies between [p,(√(p^2 +2)) ] =[I,I+f] [x]=I that implies [x]=p](https://www.tinkutara.com/question/Q49677.png)