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if-x-x-x-x-2020-2020-Solve-for-x-




Question Number 98968 by Brokris last updated on 17/Jun/20
if x^x^x^x^(2020)    = 2020.  Solve for x
ifxxxx2020=2020.Solveforx
Commented by mr W last updated on 17/Jun/20
x^x^(...x^(2020) )  =2020  has the same root as  x^(2020) =2020  x=±((2020))^(1/(2020)) ≈±1.00377
xxx2020=2020hasthesamerootasx2020=2020x=±20202020±1.00377

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