Question Number 25054 by Sattwik Chakraborty last updated on 02/Dec/17
$${If}\:{x}:{y}=\mathrm{5}:\mathrm{2},\:{then}\:{find}\:{the}\:{value}\:{of}\:\left(\mathrm{8}{x}+\mathrm{9}{y}\right)/\left(\mathrm{8}{x}+\mathrm{27}\right) \\ $$
Answered by $@ty@m last updated on 02/Dec/17
$$\frac{\mathrm{8}{x}+\mathrm{9}{y}}{\mathrm{8}{x}+\mathrm{27}{y}} \\ $$$${Divide}\:{Nr}\:\&{Dr}\:{by}\:{y} \\ $$$$\frac{\mathrm{8}\frac{{x}}{{y}}+\mathrm{9}}{\mathrm{8}\frac{{x}}{{y}}+\mathrm{27}} \\ $$$$=\frac{\mathrm{8}×\frac{\mathrm{5}}{\mathrm{2}}+\mathrm{9}}{\mathrm{8}×\frac{\mathrm{5}}{\mathrm{2}}+\mathrm{27}}\:\left(\because\frac{{x}}{{y}}=\frac{\mathrm{5}}{\mathrm{2}}\right) \\ $$$$=\frac{\mathrm{40}+\mathrm{18}}{\mathrm{40}+\mathrm{54}} \\ $$$$=\frac{\mathrm{58}}{\mathrm{94}} \\ $$$$=\frac{\mathrm{29}}{\mathrm{47}} \\ $$