Question Number 112803 by Aina Samuel Temidayo last updated on 09/Sep/20
$$\mathrm{If}\:\mathrm{x}+\mathrm{y}+\mathrm{z}=\mathrm{0},\: \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} }{\mathrm{x}^{\mathrm{2}} −\mathrm{yz}}\:\mathrm{is} \\ $$
Answered by MJS_new last updated on 09/Sep/20
$${z}=−\left({x}+{y}\right)\:\Rightarrow\:\frac{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} }{{x}^{\mathrm{2}} −{yz}}=\mathrm{2} \\ $$
Commented by Aina Samuel Temidayo last updated on 09/Sep/20
$$\mathrm{Solution}? \\ $$
Commented by MJS_new last updated on 09/Sep/20
$$\mathrm{just}\:\mathrm{insert}\:\mathrm{and}\:\mathrm{calculate} \\ $$