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if-x-y-z-gt-0-and-xyz-8-prove-that-1-x-2-8-1-y-2-8-1-z-2-8-1-4-




Question Number 149036 by mathdanisur last updated on 02/Aug/21
if   x;y;z>0   and   xyz=8   prove that:  (1/(x^2  + 8)) + (1/(y^2  + 8)) + (1/(z^2  + 8)) ≤ (1/4)
ifx;y;z>0andxyz=8provethat:1x2+8+1y2+8+1z2+814
Answered by dumitrel last updated on 02/Aug/21
p^3 ≥27r⇒p≥6  q^2 ≥3pr⇒q≥12  Σ(1/(x^2 +8))=(3/8)+Σ((1/(x^2 +8))−(1/8))=(3/8)−(1/8)Σ(x^2 /(x^2 +8))≤  ≤(3/8)−(1/8)∙(p^2 /(p^2 −2q+24))≤^• (1/4)  •⇔(p^2 /(p^2 −2q+24))≥1⇔q≥12
p327rp6q23prq12Σ1x2+8=38+Σ(1x2+818)=3818Σx2x2+83818p2p22q+2414p2p22q+241q12
Commented by mathdanisur last updated on 02/Aug/21
Cool, Thank You Ser
Cool,ThankYouSer

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