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If-x-y-z-gt-0-then-4x-2-x-y-8y-2-y-z-4z-2-z-x-2x-5y-z-




Question Number 154384 by mathdanisur last updated on 17/Sep/21
If  x;y;z>0  then:  ((4x^2 )/(x+y)) + ((8y^2 )/(y+z)) + ((4z^2 )/(z+x)) ≥ 2x + 5y + z
Ifx;y;z>0then:4x2x+y+8y2y+z+4z2z+x2x+5y+z
Answered by ghimisi last updated on 18/Sep/21
4((x^2 /(x+y))+(y^2 /(y+z))+(y^2 /(y+z))+(z^2 /(x+z)))≥4∙(((x+y+y+z)^2 )/(x+y+y+z+y+z+x+z))=  =4∙(((x+2y+z)^2 )/(2x+3y+2z))≥^• 2x+5y+z  •⇔4(x+2y+z)^2 ≥(2x+5y+z)(2x+3y+2z)⇔...⇔(y−z)^2 ≥0
4(x2x+y+y2y+z+y2y+z+z2x+z)4(x+y+y+z)2x+y+y+z+y+z+x+z==4(x+2y+z)22x+3y+2z2x+5y+z4(x+2y+z)2(2x+5y+z)(2x+3y+2z)(yz)20
Commented by mathdanisur last updated on 18/Sep/21
Very nice Ser, thankyou
VeryniceSer,thankyou

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