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If-xcos-ycos-zcos-0-xsin-ysin-zsin-0-and-xsec-ysec-zsec-0-then-prove-that-x-2-y-2-z-2-2-4x-2-y-2-




Question Number 157031 by PRITHWISH SEN 2 last updated on 18/Oct/21
If  xcos θ+ycos ∅+zcos ψ=0,        xsin θ+ysin ∅+zsin ψ=0  and xsec θ+ysec ∅+zsec ψ=0  then prove that            (x^2 +y^2 −z^2 )^2 = 4x^2 y^2
Ifxcosθ+ycos+zcosψ=0,xsinθ+ysin+zsinψ=0andxsecθ+ysec+zsecψ=0thenprovethat(x2+y2z2)2=4x2y2

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