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if-xy-y-2-zx-48-where-x-y-z-are-three-positive-real-numbers-then-find-the-maximum-possible-value-of-the-product-xyz-




Question Number 175793 by infinityaction last updated on 07/Sep/22
  if xy+y^2 +zx = 48; where x,y,z    are three positive real numbers    then find the maximum possible    value of the product (xyz)
ifxy+y2+zx=48;wherex,y,zarethreepositiverealnumbersthenfindthemaximumpossiblevalueoftheproduct(xyz)
Commented by LordKazuma last updated on 07/Sep/22
is this true y^2 ? not yx?
isthistruey2?notyx?
Commented by infinityaction last updated on 07/Sep/22
question is right sir try to solve  this problem
questionisrightsirtrytosolvethisproblem

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